Problem with long?

Programming Questions

asimes

in Programming Questions • 1 year ago

Sorry, this is probably a very dumb question, but I've never used long. The reference said that long uses 64 bits instead of int's 32. I tried this out:

long test = 0xfffffffff; // 9 fs
void setup() {
size(100, 100);
println(test);
}

and I got the error "The literal 0xfffffffff of type int is out of range". What am I doing wrong? Also, is there a way to print a long as 0s and 1s?

Replies(2)

asimes

Re: Problem with long?

1 year ago

Some google searching gave me this: http://processing.org/discourse/beta/num_1202574327.html

Looks like I have to put "L" at the end. I still would like to know how to go about seeing a long as 0s and 1s (binary() is for int).

EDIT: As noted in the link, the reference doesn't mention putting "L" at the end. It was a bit of a headache for me to figure that out, maybe it should go there?

http://processing.org/reference/long.html

asimes

Well, never mind, figured out something good enough for my testing purposes. I'll post code incase anyone else ever wants to be able to visualize a bitboard as a print function. Also, as mentioned in the last post, it might be nice to include that "L" in the reference for future people looking to use long for the first time.

long a = 0x7fffffffffffffffL;
void setup() {
size(100, 100);
longBinary(a);
}
void longBinary(long in) {
String bin = "";
for (int i = 63; i >= 0; i--) {
long bitMask = (1L<<i)&in;
if (bitMask != 0) bin += "1";
else bin += "0";
}
println(bin);
}

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