Actually, using another variable instead of a hard-coded number would be the best solution.


Then regarding your problem:
I'm not completey sure, that i understood, what you wanted to do in "objcollenemy1()".
Pushing the other circle to the right/left when you come near it and are on the same horizontal level?

In this case you could:
1. compare the x-position of the circles and
2. if their distance is less than a certain value,
3. check wich one is bigger and move the enemy-circle accordingly.

example:

1. void objcollenemy1() {
     // minumum distance
     int minDist =50;
    
     // horizontal distance
     int xDist = enemyX-dotX;
    
     if (abs(xDist) < minDist && dotY == enemyY) {
       if(xDist>=0){
         enemyX += minDist-xDist;
       }else{
         enemyX -= minDist+xDist;   
       }
     }
   }
   

 

hi, 

First some remarks on your code:
Your should really avoid code like this:

Copy code

1.   enemyX--;
2.   enemyX--;
3.   enemyX--;
4.   enemyX--;
   

It's much easier to write and understand if you write it in one line:

Copy code

1. enemyX += 4;
   

Actually, using another variable instead of a hard-coded number would be the best solution.

Thanks for the tip, t hat'll save me from a lot of typing. ^_^

Then regarding your problem:
I'm not completey sure, that i understood what you wanted to do in "objcollenemy1()".
Pushing the other circle to the right/left when you come near it and are on the same horizontal level?  

Sort of, I wanted to push the box to the left, when the dot was on the left of the box and the Y co-ordinates match, and vise versa when the box was on the right.

example:

Copy code

1. void objcollenemy1() {
     // minumum distance
     int minDist =50;
     
     // horizontal distance 
     int xDist = enemyX-dotX;
     
     if (abs(xDist) < minDist && dotY == enemyY) {
       if(xDist>=0){
         enemyX += minDist-xDist;
       }else{
         enemyX -= minDist+xDist;    
       }
     }
   } 

It looks like it could work, I haven't had time to test it yet, though.

Thanks :)