n00b question about remainder after division

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Sparked

n00b question about remainder after division

in Programming Questions • 1 years ago

If I calculate 10/7 the result is 1.428571429. Is there anyway I can get processing to give me just the remainder 0.428571429? I was reading about the using %(modulo) but I'm not sure this is what I need.

For example when I use the code:

void setup() {

float a = 7%10;

println(a) ;

}

The program just prints 7.

am I missing something here?

Replies(5)

tech37

Re: n00b question about remainder after division

1 years ago

Here what I will do :

float valueA;
float valueB;
float answerA;
float answerB;
void setup()
{
valueA = 10;
valueB = 7;
answerA = valueA % valueB; // answerB = 3;
answerB = answerA / valueB; // answerB = 0.42857143
println(answerA);
println(answerB);
}

this program is compile,tested and work.

Sparked

Re: n00b question about remainder after division

1 years ago

Excellent! Thank you for the quick reply! Your code really helped me understand what the "%" does and where it was getting the 3 from.

kooogy

Re: n00b question about remainder after division

1 years ago

> am I missing something here?

yes, what the % operator does. it's the modulo, not the remainder

http://processing.org/reference/modulo.html

you probably want something like (a / (float)b) - (int)(a / b). (untested)

beware the integer division problem.

tech37

Re: n00b question about remainder after division

1 years ago

Here my understanding about modulo %.

Think fractions like : 2/3 or 10 3/7. Let say in your example 10 / 7 = (10 + x ) / 7 Modulo is x

So the modulo of 2/3 is 2.

rbrauer

Re: n00b question about remainder after division

1 years ago

I do it something like this:

float whole = floor(10/7);
float remainder = 10/7-whole;

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