Multi-Char array to int function

Programming Questions

rebelion5..

Multi-Char array to int function

in Programming Questions • 10 months ago

So i am designing code to convert a string such as ("AA3") to and integer and vice versa. The integer is the result of a nested loop set up that i have been trying to get to work.

char numbers[] = {
'0','1','2','3','4','5','6','7','8','9'};
char letters[] = {
'A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z'};
char test[] = {'B','G','6'};
char[] output;
int outputf; //first output
int outputs; // second output
int outputt; // third output
void setup() {
convertID(test);// testing the main function.
}
char[] convertID(int id) {
char[] output = {'A','A','0'};
return output;
}
int convertID(char[] chid) {
int outputf = 0;
int outputs = 0;
int outputt = 0;
for(int i = 0;i < letters.length;i++) {// first loop checks what character the first space is and starts filling the integer.
if (chid[0] == letters[i]) {
outputf = 270 * (int)letters[i];
}
for (int h = 0;h < letters.length;h++) { // second loop checks the second character and applys it to the int.
if(chid[1] == letters[h]) {
outputs = 10 * (int)letters[h];
}
for (int a = 0; i < numbers.length - 1;a++) { //third loop checks the number at the end for its value.
if(chid[2] == numbers[a]) {
outputt = 1 * numbers[a];
}
}
}
}
return outputf + outputs + outputt; //returns the sum of all three spaces.
}

The problem ive been encountering is that on line "if(chid[2] == numbers[a]) {" ive been getting an array out of bounds exception which means i did something wrong with the arrays.

If someone could just help me to first get rid of this error and secondly get this program to work for its intended purpose.

Thank you all in advance.

Replies(7)

el_dippo

Re: Multi-Char array to int function

10 months ago

Hi,

Your loop was wrong. I also changed the numbers array to an int array.

int[] numbers = {
0, 1, 2, 3, 4, 5, 6, 7, 8, 9
};
char letters[] = {
'A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'
};
char test[] = {
'B', 'G', '6'
};
char[] output;
int outputf; //first output
int outputs; // second output
int outputt; // third output
void setup() {
println(test);
println(" = "+convertID(test));// testing the main function.
}
char[] convertID(int id) {
char[] output = {
'A', 'A', '0'
};
return output;
}
int convertID(char[] chid) {
int outputf = 0;
int outputs = 0;
int outputt = 0;
for (int i = 0;i < letters.length;i++) // first loop checks what character the first space is and starts filling the integer.
if (chid[0] == letters[i])
outputf = 270 * (int)letters[i];
for (int h = 0;h < letters.length;h++) // second loop checks the second character and applys it to the int.
if (chid[1] == letters[h])
outputs = 10 * (int)letters[h];
for (int a = 0; a < numbers.length - 1;a++) //third loop checks the number at the end for its value.
if (chid[2] == numbers[a])
outputt = 1 * numbers[a];
return outputf + outputs + outputt; //returns the sum of all three spaces.
}

rebelion5..

Re: Multi-Char array to int function

10 months ago

This is great! Thank you very much. The only issue i have is it doesn't seem to be returning the correct numbers as in AA1 should make 1 but it makes 18200. Any ideas on how to remedy this?

EDIT: So i looked into it and i believe the problem is originating from the index numbers of the letters not starting from zero but 97. This makes it so when i put an a in it dosent add 1 * CORRECT_LETTER it adds 97 * CORRECT_LETTER.

I would imagine i would have to start by either creating an overlay for the letters with their values or change the values themselves but i think those are the ASCII values so they cannot be changed.

Any help would be appreciated.

el_dippo

Re: Multi-Char array to int function

10 months ago

No problem. I don't know what you're end goal is. Nevertheless i updated the code, but i don't think this is what you want. Btw, the numbers array is absolete.

char[] numbers = {
0, 1, 2, 3, 4, 5, 6, 7, 8, 9
};
char[] letters = {
'A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'
};
char[] test = {
'A', 'A', '1'
};
char[] output;
int outputf; //first output
int outputs; // second output
int outputt; // third output
void setup() {
println(test);
println(" = "+convertID(test));// testing the main function.
}
char[] convertID(int id) {
char[] output = {
'A', 'A', '1'
};
return output;
}
int convertID(char[] chid) {
int outputf = 0;
int outputs = 0;
int outputt = 0;
for (int i = 0; i < letters.length; i++) // first loop checks what character the first space is and starts filling the integer.
if (chid[0] == letters[i])
outputf = ((int)letters[i]-65);
for (int h = 0; h < letters.length; h++) // second loop checks the second character and applys it to the int.
if (chid[1] == letters[h])
outputs = ((int)letters[h]-65);
outputt = Character.getNumericValue(chid[2]);
return outputf + outputs + outputt; //returns the sum of all three spaces.
}

rebelion5..

Re: Multi-Char array to int function

10 months ago

Thank you for all your help, i made the code fully functional by overlaying an array of numbers over the letters array with each of their values. Then I add the value of that character to the end result.Now i just have to reverse engineer it and get to work on the overridden function.Anyone that finds this feel free to use my code for whatever purposes you have.

char[] numbers = {
0, 1, 2, 3, 4, 5, 6, 7, 8, 9
};
char[] letters = {
'A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'
};
char[] lettersV = {
0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21,22, 23, 24, 25
};
char[] test = {
'A', 'A', '1'
};
char[] output;
int outputf; //first output
int outputs; // second output
int outputt; // third output
void setup() {
println(test);
println(" = "+convertID(test));// testing the main function.
}
char[] convertID(int id) {
char[] output = {
};
return output;
}
int convertID(char[] chid) {
int outputf = 0;
int outputs = 0;
int outputt = 0;
for (int i = 0; i < letters.length; i++) // first loop checks what character the first space is and starts filling the integer.
if (chid[0] == letters[i])
outputf = lettersV[i]*270;
for (int h = 0; h < letters.length; h++) // second loop checks the second character and applys it to the int.
if (chid[1] == letters[h])
outputs = lettersV[h]*10;
outputt = Character.getNumericValue(chid[2]);
return outputf + outputs + outputt; //returns the sum of all three spaces.
}

rebelion5..

Re: Multi-Char array to int function

10 months ago

So i ran into another error while i was working on the overridden calls im sure it something simple but i cant figure it out.

This is the opposite of the first function where i return the characters from a float input.

The problem is after i did all this was the first two loops work perfectly, but the last part for the numbers wont go into the character array output. This code will print 'B' 'F' ' ' where it should print 6 in the third space. It probably has something to do with the conversions because if i put a println and print number count it comes out as 6 just as expected.

These two places are where i tracked the errors most likely locations to be.

char output3 = char(numbercount);

output[2] = output3;

and if necessary to have the full code i can edit in.

char[] convertID(float id) {
char[] output = {0,0,0};
////////////////////////////////////////////Majors/main below here
int maincount = int(id) / 270 ;
float mainremainder = id % float(270);
int subtractmajor = maincount * 270;
id = int(id) - subtractmajor;
////////////////////////////////Minors below here
int minorcount = int(id) /10;
float minorremainder = id % float(10);
int subtractminor = minorcount * 10;
id = int(id) - subtractminor;
//////////////////////////////Numbers Below here
int numbercount = int(id) / 1;
int subtractnumber = numbercount * 1;
id = int(id) - subtractnumber;
println(numbercount);
char output1 = '0';
char output2 = '0';
char output3 = char(numbercount);
for(int i = 0;i < letters.length;i++) {
if (i == maincount) {
output1 = letters[i];
}
}
for(int f = 0;f < letters.length;f++) {
if (f == minorcount) {
output2 = letters[f];
}
}
output[0] = output1;
output[1] = output2;
output[2] = output3;
return output;
}

el_dippo

Re: Multi-Char array to int function

10 months ago

I think to problem lies here:
char output3 = char(numbercount);

I think it should be:
char output3 = (char) numbercount;

Why println prints it correctly? Because println checks what you want to see, and converts the variables to string in case a conversion is needed. This means that you would expect a error with println, but won't get a error but the correct value as a result.
I believe you get the error if you type:

char output3;
println(output3 = char(numbercount));

Plz upload the full code (i couldn't test this code) or start a new thread in case you have a new question.

rebelion5..

Re: Multi-Char array to int function

10 months ago

I tired what you suggested and it still returns a blank for the third character. I need to convert numbercound directly into a char(that is represents a number). I have no idea why its returning a blank for the last char in the array, but sometimes the length of spaces in the blank changes, i dont know if that has anything to do with it.

PS: Thank you for all your help i dont think i would've been able to do it without you.

Full Code:

char[] numbers = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9};
char[] letters = {'A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'};
char[] lettersV = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21,22, 23, 24, 25};
char[] test = {'Z', 'Z', '9'};
char[] output;
int outputf; //first output
int outputs; // second output
int outputt; // third output
void setup() {
//println(test);
//println(" = "+convertID(test));// testing the main function.
println(convertID(7008.0));
}
char[] convertID(float id) {
char output1 = 0;
char output2 = 0;
char output3 = 0;
char[] output = {0,0,0};
int idcopy = int(id);
if(idcopy < 7010) {
////////////////////////////////////////////Majors/main below here
int maincount = int(id) / 270 ;
float mainremainder = id % float(270);
int subtractmajor = maincount * 270;
id = int(id) - subtractmajor;
////////////////////////////////Minors below here
int minorcount = int(id) /10;
float minorremainder = id % float(10);
int subtractminor = minorcount * 10;
id = int(id) - subtractminor;
//////////////////////////////Numbers Below here
int numbercount = int(id) / 1;
int subtractnumber = numbercount * 1;
id = int(id) - subtractnumber;
output1 = '0';
output2 = '0';
output3 = (char) numbercount;
for(int i = 0;i < letters.length;i++) {
if (i == maincount) {
output1 = letters[i];
}
}
for(int f = 0;f < letters.length;f++) {
if (f == minorcount) {
output2 = letters[f];
}
}
}
else {
println("Input is over the maximum value");
}
output[0] = output1;
output[1] = output2;
output[2] = output3;
if(idcopy < 7010) {
return output;
}
else {
output[0] = ' ';
output[1] = ' ';
output[2] = ' ';
return output;
}
}
int convertID(char[] chid) {
int outputf = 0;
int outputs = 0;
int outputt = 0;
for (int i = 0; i < letters.length; i++) // first loop checks what character the first space is and starts filling the integer.
if (chid[0] == letters[i])
outputf = lettersV[i]*270;
for (int h = 0; h < letters.length; h++) // second loop checks the second character and applys it to the int.
if (chid[1] == letters[h])
outputs = lettersV[h]*10;
outputt = Character.getNumericValue(chid[2]);
return outputf + outputs + outputt; //returns the sum of all three spaces.
}

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