move a point away

Programming Questions

clankill3r

in Programming Questions • 1 year ago

How can i move a point up and down and left and right.

It has to be a bit smooth but not like sin and cos for a perfect circle.

I did a few attempts, either it's jagging or it moves in one direction.

Also if i use it for more points then they should not do all the same.

float x1, y1;
void setup() {
size(400, 400);
x1 = width/2;
y1 = height/2;
}
void draw() {
background(0);
x1 += noise(frameCount) - noise(frameCount)/2;
y1 += noise(frameCount) - noise(frameCount)/2;
ellipse(x1, y1, 5, 5);
}

Replies(2)

quarks

Re: move a point away

1 year ago

Lines 12 & 13 are effectively

x1 += noise(frameCount)/2;
y1 += noise(frameCount)/2;

Also noise(n) always returns

the same value for the same n
a value in the range 0.0 - 1.0 for any value of n

This means that the point will always move at 45 degrees.

If I understand the problem you want the point to move in a 'rough' circle. I suggest that the solution to your problem is to use sin and cos BUT vary the radius slightly using the noise function.

clankill3r

Re: move a point away

1 year ago

thanks, i use this now:

float nx1 = x1 + sin(radians(frameCount60))*30;
float ny1 = y1 + cos(radians(frameCount60))*30;
float nz1 = z1 + sin(radians(frameCount60))*30;
float ncx1 = cx1 + sin(radians(frameCount60))*-50;
float ncy1 = cy1 + cos(radians(frameCount60))*-50;
float ncz1 = cz1 + sin(radians(frameCount60))*-50;
float ncx2 = cx2 + sin(radians(frameCount60))*20;
float ncy2 = cy2 + cos(radians(frameCount60))*20;
float ncz2 = cz2 + sin(radians(frameCount60))*20;
float nx2 = x2 + sin(radians(frameCount60))*-80;
float ny2 = y2 + cos(radians(frameCount60))*-80;
float nz2 = z2 + sin(radians(frameCount60))*-80;

could use random for the multiply but it's fine atm.

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move a point away

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