Image upload failed using PHP

simy202

Image upload failed using PHP

in Integration and Hardware • 2 years ago

Hi,

This is probably a simple question, however I am finding it difficult to accomplish.

<?php
$upload = new upload();
$upload->upload_file();
?>
so in a test page it would be like so:
<?php
$upload = new upload();
$upload->upload_file();
?>
<form action="" method="post" enctype="multipart/form-data">
<input type="file" id="real_upload" class="hide" name="file" />
<input type="submit" id="real_submit" class="hide" value="Upload" />
</form>

The problem is I'm using this upload system for parts of the website, what I want is to have this class upload the file once it has gone through the "gallery upload" segment:

<?php
$mysql_link = mysql_connect("localhost", "", "");
mysql_select_db("") or die("Could not select database");
while($counter <= count($photos_uploaded)) {
if($photos_uploaded['size'][$counter] > 0) {
if(!array_key_exists($photos_uploaded['type'][$counter], $known_photo_types)) {
$result_final .= "File ".($counter+1)." is not a photo<br />";
}
else {
mysql_query( "INSERT INTO gallery_photos(`photo_filename`, `photo_caption`, `photo_category`) VALUES('0', '".addslashes($photo_caption[$counter])."', '".addslashes($_POST['category'])."')" );
$new_id = mysql_insert_id();
$filetype = $photos_uploaded['type'][$counter];
$extention = $known_photo_types[$filetype];
$filename = $new_id.".".$extention;
mysql_query( "UPDATE gallery_photos SET photo_filename='".addslashes($filename)."' WHERE photo_id='".addslashes($new_id)."'" );
}
?>

How would I approach this PHP Image Gallery (Upload Problem)?

Thanks

Replies(1)

PhiLho

Re: Image upload failed using PHP

2 years ago

Do you know this is a Processing forum, not a PHP forum? I see no Processing code here!

(Beside, it doesn't belong to Programming questions, which are for code for Processing "out of the box", so I moved it.)
Now, I will do a stretch of imagination and suppose you are meaning to talk about a Processing sketch uploading the images it creates to a Web site.
The issue is that I don't understand what your exact problem is...
You show fragments of code which look more or less OK (I don't think you need to slash the new_id, but it doesn't hurt) but we don't know where they are inserted, nor what is your problem/bug/difficulty exactly.

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