A " list of arrays"? Really? Or an array of numbers?
" can someone create an object for me"
Not really, policy here, even more for homework, is to guide and help, not to code in place of the student...

" i have no idea where to start"
In general, it is a good idea to search the forum, this kind of request have been already made.
Also look at the tutorials and the examples.
Useful stuff: arrays, for loops, fill(), rect().

That's not hard, think about the assignment, try to make something, show it here, we will guide you to improve it.

Try to take the problem from another side: make an array of numbers, filled by using a for loop. Then in draw(), loop over the array, and for each number, compute an offset (where to draw the rectangle) and a size based on the number. Then use rect() to draw this rectangle.

2. ////// practice-array-1.pde // Display all elements of an array (with bar charts, etc.)
3. 
   
4. float [] a = { 99.1, 33.2, 344.3, 22.4, 66.7 };
5. int many=  a.length;
6. int nextX, nextY;        // Coords of next display.
7. final int FIRSTX=10, FIRSTY=20, SPACING=12;
8. 
   
9. float big=100,  multiplier;
10. 
    
11. void setup()
12. {
13.   size( 800,480);
14. text("practice-array-1 // Display all elements of an array (with bar charts, etc.", 10, height-20 );
15. }
16. void draw()    // Show all values;
17. {
18.    //  big=  biggest( a );              // Find biggest value in a.
19.    // big=  biggest( a );              // Find biggest value in a.
20.  
21.    
22.    int k=  whereBig( a );
23.    big=  a[ k ];              // Gets  biggest value in a.
24. 
    
25.  
26.    multiplier=  (width-90) / big;
27. 
    
28.   //scene();
29.   show();
30. }
31. void scene() { 
32.   background( 255,255,200 ); 
33. }
34. 
    
35. void show()      //// Show elements of array.
36. {
37.   nextX=  FIRSTX;
38.   nextY=  FIRSTY;
39.   for (int j=0; j<many; j++ )
40.   {
41.     display( a[j] );
42.   }
43. }
44. void display( float v )    //// display one value on the screen. 
45.                             // ++++ Note to self:  maybe later I'll figure out how to make a bar.
46. {
47.   fill(0);
48.   text( v, nextX, nextY );
49.   bar( v );
50.   nextY += 15;
51. }
52. void bar( float v )        //// Draw a bar.
53. {
54.   float x, y, w, h;
55.   x= nextX + 60;
56.   y=  nextY - SPACING;
57.   w=  v * multiplier;
58.   h=SPACING-2;
59.   // Draw the bar.
60.   fill(255,0,0);
61.   rectMode( CORNER );
62.   rect( x,y, w, h );
63. }
64.                             
65. 
    
66. float biggest( float[] z )        // Retgurn biggest value in this array.
67. {
68.   float result; 
69.   result=  z[0]; 
70.   for ( int j=0; j < z.length; j++)
71.   {
72.     if (z[j] > big) result=  z[0]  ;    /// replace with bigger value.
73.   }
74.   return result;
75. }
76. int  whereBig( float[] z )        // Return INDEX OF the biggest value in this array.
77. {
78.   int w=0;  
79.   for ( int j=0; j < z.length; j++)
80.   {
81.     if (z[j] > z[w]) w=j;        // replace w with INDEX of bigger value!
82.   }
83.   return w;

is there an easier way to write this program?

Easier? Not really. Looks quite good already. You can get rid of the biggest() function which doesn't seem to be used (it is incorrect, you should have result = z[j] in the loop).
There are some steps that can be simplified, you can rely less on global variables, but otherwise, it works.
Look at nfc() and similar for better alignment on the decimal point.

I still wonder about your picture.