How to narrow down the rita.wordnet dictionary to simple english dictionary~

xliu02

How to narrow down the rita.wordnet dictionary to simple english dictionary~

in Contributed Library Questions • 11 months ago

Hi~
I tried to make my sketch recognize two-letters simple words, I use rita.wordnet, but now it recognize all abbreviations. Could I just make it recognizes simple words, like "go", "us", "we"?

I would appreciate any advice that will achieve this result or if you know of any other Processing code that will accomplish the same task.

Thank you!!

Replies(2)

tfguy44

Re: How to narrow down the rita.wordnet dictionary to simple english dictionary~

11 months ago

Some quick math shows that there are only 676 possible two letter words.

You might have better luck if you generated a simple list of all the possible ones, removed any that aren't words, and then checked for words in that list instead.
Sometimes simple is best!

String[] ws = new String[676];
int i = 0;
for( char x = 'A'; x <= 'Z'; x++ ){
for( char xx = 'A'; xx <= 'Z'; xx++ ){
ws[i] = "" + x + xx;
i++;
}
}
for( i = 0; i < ws.length; i++ ){
println( ws[i] );
}

xliu02

Re: How to narrow down the rita.wordnet dictionary to simple english dictionary~

11 months ago

This is my code~~ I am really a newbie in processing. Could you tell me how to modify it please？ Thank you so so much!!!

for (int i = 0; i< balls.size(); i++) {

      Ball bi = (Ball)others.get(i);
      float cx = bi.x - x;
      float cy = bi.y - y;

      float distance = sqrt(cx*cx + cy*cy);
      float minDist = 1.2 * r;

      if (bi != this && distance < minDist) {

        String[] s1 = {
          str
        };
        String[] s2 = {
          bi.str
        };

        String[] s3 = concat(s1, s2);

        if (wordnet.exists(s1[0]+s2[0])) {

          println(s1[0]+s2[0]);

          ball_fill_color = color(255, 0, 0, 255);
          bi.ball_fill_color = color(255, 0, 0, 255);

        }
else {

          float angle = atan2(cy, cx);
          float targetX = x + cos(angle) * minDist;
          float targetY = y + sin(angle) * minDist;
          float ax = (targetX - bi.x) * spring;
          float ay = (targetY - bi.y) * spring;
          vx -= ax;
          vy -= ay;
          bi.vx += ax;
          bi.vy += ay;
        }
      }
    }
}

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