prints yes, counting starts at 0

1. String mystring = "abcdefg";
2. char ase;
3. ase = mystring.charAt(2);
4. println ("Start");
5. if (ase == 'c') {
6.   //----> run statement
7.   println ("yes");
8. }
9. else {
10.   println ("no");
11. }

interesting for you?

1. String mystring = "abcdefg";
2. char ase;
3. ase = mystring.charAt(2);
4. println ("Start");
5. if (ase == 'c') {
6.   //----> run statement
7.   println ("yes1");
8. }
9. else {
10.   println ("no1");
11. }
12. // ------------------------------------------------
13. if (mystring.contains ("d")) {
14.   //----> run statement
15.   println ("yes2, at: " + mystring.indexOf ("d") );
16. }
17. else {
18.   println ("no2.");
19. }

yes it's work....

i'm really thank you for you....

ow sorry i'm forget...

how about integer?

1. int val = 12345;
2. if (val.contains ("2"))-------->  can't work

or maybe different function?

ok nice...

regard..

with int you can do a lot of other stuff than with Strings.

With int you can ask:

• is it < than something
  
• is it >
• is it ==
• is it <=
• is it >=
• is it without a rest when devided by 5 (use % to ask what is the rest)
• you can add and sub ints etc.

all this makes no sense with Strings   

for Strings is an own section in the reference called

String Functions

which contains

String Functions

http://www.processing.org/reference/


see also
http://www.processing.org/reference/String.html