How i can save the position of a rect() in a 2 dimensional array?

Programming Questions

oreca1

How i can save the position of a rect() in a 2 dimensional array?

in Programming Questions • 5 months ago

Hey guys! First: Sorry for my bad english :(

so, this is my code:

void setup(){

size(640, 480);
background(255);

fill(0);

for(int i=0; i<10; i++){
rect(random(630), random(470), 10, 10);
}
}

void draw(){

}

No i want to save the position of the random created rects in a 2 dimensional array. But i have no idea how to do it :( And google does not help :(

if someone could help, that would be great :)

Replies(3)

Chrisir

Re: How i can save the position of a rect() in a 2 dimensional array?

5 months ago

you need no 2D array

just a normal 1D array of type PVector

PVector [] rects = new PVector [300];

rects[i].x=.....

rects[i].y=.....

tfguy44

Re: How i can save the position of a rect() in a 2 dimensional array?

5 months ago

// Create a 2D array to store the data.
float[][] anArray = new float[10][2];
void setup() {
size(640, 480);
fill(0);
for (int i=0; i<10; i++) {
// Create some meaningful data, storing it in the array.
anArray[i][0] = random(630);
anArray[i][1] = random(470);
}
}
void draw() {
background(255);
// Draw rectangles based on saved data.
for (int i=0; i<10; i++) {
rect(anArray[i][0], anArray[i][1], 10, 10);
}
}

oreca1

Re: How i can save the position of a rect() in a 2 dimensional array?

5 months ago

Nice! thx. guys!

Top Reply