I'm not quite sure what you mean. Processing provides standard trig function ( cos(), sin(), tan()), and others ( atan2() is also useful). You can find the coordinates of a point a specific distance from another point using cos() (for the X) and sin() (for the Y).

maybe read
http://www.processing.org/learning/trig/
http://www.openprocessing.org/sketch/62744

for what you want to do you don't need sin and cos I think

just add
-10, -9, -8 ...... 7,8,9,10
to your
x,y in a double for loop e.g.

1. for x_i = -10..... 10
2.    for y_i = -10..... 10
3.      point (x+x_i,y+y_i);
4. }
5. }

Sorry if I confused you guys quite a bit. But basically the program will create the shape on input. It should test to see if the object being created on input is outside the "boundaries" of the current object. This is a anti-collide feature being implemented. I have it now but it only works for Up, Down, Left, and Right of the object. I want it where it will test the boundaries if the object was being made at any degrees between 0 and 90.

Hello,


The distance

Or are you looking for distance between the two objects?
The distance takes into account both x and y.

Then use dist()

http://www.processing.org/reference/dist_.html

it's

1. float myDistance = dist (original_x, original_y, new_x, new_y );

then

1. if (myDistance < 60) {
2.   // collide
3. }

The angle between the two

To really get the angle between the two maybe use

1. float myAngleBetween (PVector myPVector1, PVector myPVector2) {
2.   float a = atan2(myPVector1.y-myPVector2.y, myPVector1.x-myPVector2.x);
3.   if (a<0) { a+=TWO_PI; }
4.   return a;
5. }

Good luck!

Greetings, Chrisir  

Hey thanks. I will give it a few tries and see if I can get it to work.

I had an error in the last code, corrected it, new line is bold.