help--processing.app.SketchException: unexpected char: 'J'

Programming Questions

Omnimusha

help--processing.app.SketchException: unexpected char: 'J'

in Programming Questions • 7 months ago

e.g

This character does not accept " \".

how I can change '/' ??

String s="D:\JOSE\Processing\BLUETOOCH\data\pos.txt";

e.g 2:

void setup() {
selectInput("Select a file to process:", "fileSelected");
}

void fileSelected(File selection) {
if (selection == null) {
println("Window was closed or the user hit cancel.");
} else {
println("User selected " + selection.getAbsolutePath());
}

}

D:\JOSE\Processing\BLUETOOCH\data\imagenes\avatar66125_0.gif

Replies(4)

calsign

Re: help--processing.app.SketchException: unexpected char: 'J'

7 months ago

The \ character, in Java, is an escape character used to create special characters in the text such as \n for a new line. When Processing says that it doesn't expect J, that is because it falls after a backslash. The escape character for \, then, is \\, so you'll need to change all of your backslashes to double backslashes.

Omnimusha

Re: help--processing.app.SketchException: unexpected char: 'J'

7 months ago

Thanks for your help, now does work!

txt file: C:\Users\Omnimusha\Desktop\a5abb2.bmp

void setup(){
     selectInput("Select a file to process:", "open_");
}

String temp="";
void open_(File selection) {

String lines[] = loadStrings(selection.getAbsolutePath());
println("there are " + lines.length + " lines");
for (int i = 0 ; i < lines.length; i++) {
println(lines[i]);
}

    String[] pieces = split(lines[0], "\\");

for(int i=0;i<pieces.length;i++){

    temp+=pieces[i];
    if( pieces.length-1 !=i ){
    temp+="/";
    }

}
    println(temp);



}