floor, and round functions give wrong results.

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davos111

in Programming Questions • 1 years ago

this fails:

float x=20110801.88;

int a = floor(x);

println(a);

isung processing 64 bits, on mac.

Replies(2)

jbum

1 years ago

The float data type doesn't have enough precision to store the number, as you'll see if you do this:

float x=20110801.88;

System.out.printf("%9.2f\n", x);

You can work around it by using doubles:

double x=20110801.88d;

int a = (int) Math.floor(x);

Note: The size of the float() data type is fixed to 32 bits, regardless of whether you are using a 64 bit architecture or not.

1 years ago

thank you :)