1. for(int i=0;i<a.length;i++){if((a[i]%2==0)||(a[i]%10==0)){println(a[i]);}}

All multiples of 10 are also even, because 10 is even. So you don't actually need to check separately for multiples of 10. If you catch all the even numbers, you'll get them anyway.

1. for(int i=0;i<a.length;i++) {
2.       if(a[i]%2==0){
3.             println(a[i]);
4.       }
5. }