color() on a PGraphics canvas in the Processing IDE

Core Library Questions

vaetxh

color() on a PGraphics canvas in the Processing IDE

in Core Library Questions • 3 months ago

Hi,

The setup of my sketch means that I need to call color(float r, float g, float b) on a PGraphics canvas because I have set the colorMode of the canvas to be different from the main colorMode. However, the IDE interprets this as a cast and gets confused about the '.' in canvas.color(0.1, 0.6, 0.8). Looking at the source, PGraphics does have a color() method. Is there any way to trick the IDE in using that rather than a cast?

Thanks,

Rob

Replies(4)

GoToLoop

Re: color() on a PGraphics canvas in the Processing IDE

3 months ago

1st: color() is not a cast operator; it's 1 of the many PApplet's methods you can find below:

http://processing.org/reference/

http://processing.org/reference/color_.html

Its cast operator is between parens -> ( color).

And in Java, it's actually syntactic sugar for -> ( int).

Now, if you create methods that happen to have the same name as 1 of the PApplet's,

you end up overshadowing it in that particular class.

canvas.color(.1, .6, .8); would not be invoking Processing's own color() method,

but rather from the class variable canvas references!

However, if variable canvas points to a PGraphics' object, it would also be using a PApplet's color().

The only catch is that color() and any other methods would be bound to any settings

to that particular PGraphics' instance, rather than general main screen's settings.

vaetxh

Re: color() on a PGraphics canvas in the Processing IDE

3 months ago

Thanks for the reply. I'm aware of the way color works, as when I use it in Eclipse, I can call it as expected: canvas.color(...) but in the Processing IDE I'm unable to do this as it complains about an unexpected token '.'. How can I get around this?

Thanks,

Rob

tfguy44

Re: color() on a PGraphics canvas in the Processing IDE

3 months ago

PGraphics pg;
color c, k;
void setup(){
size(400,200);
pg = createGraphics(200,200,P2D);
pg.beginDraw();
pg.background(0);
pg.colorMode(HSB,100);
pg.noStroke();
// c = pg.color(0,100,100); // red // ERROR - unexpected token: .
pushStyle(); // Save current color mode.
colorMode(HSB,100); // Switch to using the other canvas' color mode.
c = color(0,100,100); // Using the other canvas' color mode, define "red".
popStyle(); // Restore the saved color mode.
k = color(0,100,100); // Now this is teal.
pg.fill(c);
pg.ellipse(100,100,100,100); // Red ellipse
pg.endDraw();
background(255);
noStroke();
fill(k);
rect(50,50,100,100); // Teal rectangle
image(pg.get(),200,0);
noLoop();
}
void draw(){} // Do nothing.

PhiLho

Re: color() on a PGraphics canvas in the Processing IDE

3 months ago

vaetxh, your descriptions are confusing (for me, at least, I am only half awake).
Perhaps showing a line or two of code can help understanding what you mean.

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