( t.indexOf(word[0]) != -1)
I've find out this stuff and it work pretty good ,
but now i don't know how can i set his position like it need to replace the word at his position

String t ="c'est ici";

  word[0]="ici";
  translate(20,20);
  text(t,  x, y);


  if ( t.indexOf(word[0]) != -1) {
    fill(255, 0, 0);
    text("///", 0, 0);
  }


Maybe textWidth(t.substring(word[0])) can solve this but i can't use it that way...

I can't figure out exactly what you want.
Is it anything similar to this?:

String sentence = "I ate 1 apple and 3 bananas!";
String[][] foodEx = { {"apple", "pear"}, {"banana", "açaí"} };

println(sentence);

for ( int i = foodEx.length; i != 0; 
sentence = sentence.replaceAll( foodEx[--i][0], foodEx[i][1] ) );

println(sentence);

exit();

Nice ! Thanks its a part of what i wanted !
Do you think i can be able to replace the a letter by a image or a pattern? I'm gonna try this .
But i'm not sure to understand all the code
i don't understand that part

for ( int i = foodEx.length; i != 0; 

What does i != 0 means? 

and also that one ?

( foodEx[--i][0], foodEx[i][1] )

i don't understand the --i part ? 

!= means NOT EQUAL / IS DIFFERENT.
In some other languages, it can be <> instead.

--i means -> 1st subtract 1 from i, only then return the value of i.

You can consult Processing's reference for it!  

Thanks a lot  !
I'm trying to make it work with only one string  but doesn't lauch
int x=0;
int y=0;
size(500,500);
String text = "Je veux etre ici mais également la";
String[] foodEx =  {"ici", "cool"} ;
translate(50,50);
text(text, x, y);
for ( int i = foodEx.length; i != 0;
text = text.replaceAll(foodEx[--i][0])  );


text(text, x, y+30);

What's wrong?

My example was using a 2D array -> String[] []
But yours is just a 1D array -> String[]

Alternatively, you can make 2 1D arrays. One for search words, and the other for replace words!

Another bug is that you provide only 1 parameter for method replaceAll(). It needs 2!

Nice thanks !

String sentence = "I ate 1 apple and 3 bananas!";
String[] find =  {"apple", "pear"};
String[] replace =  {"bananas", "orange"};

println(sentence);

for ( int i = find.length; i != 0;
sentence = sentence.replaceAll( find[--i][0], replace[i][1] ) );

println(sentence);

exit();

But still a error , i must be wrong again... it says it must be an array but it's string
I must be wrong where i put it's bold i guess

Since you're using 2 1D arrays this time, you can only use 1 index instead of 2!:
find[--i], replace[i]  instead of   find[--i] [0], replace[i] [1]

In my 2D array, the [0] index was the find words, and [1] the replace words!  

OKay thanks , it help me understand how it works to make it with 1D arrays , i've never seen 2D arrays and never used the replace.All  stuff !

i'm gonna try to experiment with that :)

Thanks again for your patience

I've tryied it with ponctuation, it's working with ? or ! But not with dot "."  , when i put a dot "." it's just replace all the letter like the example below :

String[] find =  {"."};
String[] replace =  {"?"};

The result is :

example :

I don't remember this picture.

???????????????????????

I believe method replace() is better than replaceAll() when all you want is replace 1 single character!

You can see a complete list of methods from class String at the link below:
http://docs.oracle.com/javase/6/docs/api/java/lang/String.html

wonderful! That exactly what i was looking for , i didn't find the replaceAll stufff in the processing reference , Thanks for the link
Maybe this way i will be able to overwrite instead of replace !

B/c it's not exactly Processing stuff, but Java!  

Nice ! :)
I check it and now trying to make a superposition of the two words ! But all the sentence is superposing ,
I just make it like this , because i have no idea how can i substract the reste of the sentence instead of the replaced word

String sentence = "Some word need to be overwrite";
String base = sentence;
String[] find = {
  "overwrite"
};
String[] replace = {
  "superposition"
};
int x=0;
int y = 0;
size(600, 400);
translate(50, 50);

background(255);



for ( int i = find.length; i != 0 ;
sentence = sentence.replace( find[--i],replace[0]  )); {
  pushStyle();
  fill(0);
text(sentence, x, y);
popStyle();
}
fill(0,0,255);
text(base, x, y);

I see that you open a curly brace to create a for loop block.
You have to notice that inside for's parenthesis, there are 2 semicolons to separate its 3 parameters ( ; ; )
sentence = sentence.replace( find[--i],replace[0] ) is its 3rd parameter
and only happens each time it completes a round. That is, after popStyle();!

I would definitely recommend watching this guys videos 

Thanks for you answers !  i used to forget that " sentence = sentence.replace( find[--i],replace[0] ) " is the third parameter ! haha i'm still on my way to solve this and i'm gonna check your tutorial jane 38  !
Thanks, i'll be back !