you could use println or so to check whether he recognizes BACKSPACE at all
or use int(key)==8 instead

Greetings, Chrisir
     

Chrisir meant to say that if you add println("Backspace is hit") in the place where it is tested, it allows you to see if the key is recognized.

" I suspect [...] substring is not the correct way to delete something from a string"
Just test it:

1. String textValue = "ABC";
2. textValue = textValue.substring (0,textValue.length()-1);
3. println(textValue);

for example.
Processing is great for such little quick tests...

hi,

yes, both (recognizing Backspace and substring) work in processing, but what with android?


with int (key) I meant:
try

1. if ( int(key) == 8 )
2. {
3.    textValue = textValue.substring(0,max(0,textValue.length()-1));
4. }

It's a replacement for Backspace

Greetings, Chrisir    

If you need an answer, please send me a personal message since this forum doesn't notify.

I prefer use variable keyCode rather than key.
Variable keyCode is of data-type int and key is of data-type char.

Very weird that BACKSPACE constant isn't present in Android mode?
Anyways, its actual value is '\b' -> final int BS = '\b';

kooogy, in general, your statement is true, but in the context, at the speed of a user typing characters, it isn't as critical as in a tight, big loop... Strings remain small, and the GC has the time to kick in!