ArrayIndexOutOfBoundsException does what it says on the tin:  You're trying to reference an index of an array that doesn't exist.  That often happens when you either forget to populate the array or, if you're going over it in a loop, you don't set a sensible limit.  I don't have the book you refer to so don't know the code; but I'd suggest you check the length of your array - try: "println(MyArrayName.length);" - and make sure any loops don't go beyond the array length.  Remember also that an array's index starts at zero ;)

Thanks for the tip!  The code in the book basically takes a text file with a list of location names, presents the user with those locations one line at a time and a map.  The user clicks on a map to identify where those locations are to create a locations.tsv file - adding coordinates from the map to the location list to prepare a data file for manipulation and representation.

For anyone else with the same problem the line in question is:

String name=nameTable.getString(currentRow, 1);

Changing the 1 to 0 solved the problem:

String name=nameTable.getString(currentRow, 0);

I am used to python, where lists, tuples, etc. all start with index 0 but figured processing must be different.  I guess it is a typo instead?

tom