All possible connections

General Discussion Other

mic_00

in General Discussion • Other • 8 months ago

Hi guys!

I'm new to Processing and i have only basic programing programming knowledge. I have a promblem to resolve and i hope you can help me, or at least show the right wright path to solution.

I have a number of points in 2D, i know the exact location of these.

What i need is to generate series of pictures (could be jpg or pdf) showing every possible posible single line connecting only two points (one picture = one line). Also, a good idea is to cut the number of results by ignoring lines that are shorter than XX pixels.

What I know is that I need some array and loop, but I'm a little lost.

Hope you can help.

Thanx in advance!

Replies(4)

tfguy44

Re: All possible connections

8 months ago

Well, do you have the points in an arrays at least? An array of PVectors? Or two arrays, one for X coordinates and the other for Y coordinates?

Once in an array, the code is simple:

// for each point (except for the last one in the array)
for( int i = 0; i < myPoints.length-1; i++ ){
// for each point after that point in the array
for( int j=i+1; j < myPoints.length; j++ ){
// Find the distance between the points
float d = dist( myPoints[i].x, myPoints[i].y, myPoints[j].x, myPoints[j].y );
// If that distance is long enough
if( d > longEnoughLength ){
// Clear the drawing's background
background(0);
// Draw a line between those points
stroke(255);
line( myPoints[i].x, myPoints[i].y, myPoints[j].x, myPoints[j].y );
// Save that as an image.
saveFrame("line-"+ i + "-" + j + ".png");
}
}
}

mic_00

Re: All possible connections

8 months ago

tfguy44 thanks for help,

now my code looks like this, and i get error "x cannot be resolved or is not a filed" :\

size(1000, 1000);
int[] xaxis = {
62, 59, 59, 72
};
int[] yaxis = {
452, 492, 532, 492
};
for (int i =0; i<xaxis.length-1; i++) {
for (int j=i+1; j<xaxis.length; j++) {
float d = dist(xaxis[i].x, yaxis[i].y, xaxis[j].x, yaxis[j].y);
if ( d>5) {
background(0);
stroke(255);
line (xaxis[i].x, yaxis[i].y, xaxis[j].x, yaxis[j].y);
saveFrame("line-"+ i + "-" + j + ".png");
}
}
}

tfguy44

Re: All possible connections

8 months ago

That's because you have two arrays - one for X coordinates and the other for Y. My sample code assumed you were using one array of PVectors, which is a more natural choice for an array of points.

Simply access the array elements directly, like so:

size(1000, 1000);
int[] xaxis = {
62, 59, 59, 72
};
int[] yaxis = {
452, 492, 532, 492
};
for (int i =0; i<xaxis.length-1; i++) {
for (int j=i+1; j<xaxis.length; j++) {
float d = dist(xaxis[i], yaxis[i], xaxis[j], yaxis[j]);
if ( d>5) {
background(0);
stroke(255);
line (xaxis[i], yaxis[i], xaxis[j], yaxis[j]);
saveFrame("line-"+ i + "-" + j + ".png");
}
}
}

mic_00

Re: All possible connections

8 months ago

it's working:)

Thank you very much once again!

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