Do you know a maximum amount of types of data you will be displaying? Cause if you do, then you can just turn values[] into values[][] where the first dimension will equal the number of the type, and the second dimension will equal the values for that type. Then you just turn the for loop that displays the values into a double for loop where the first loop loops through the types of data. Did I answer the right question there? Does it make sense?
Also, that's a really cool visual, I think I might use that style for one of my programs if you don't mind.

edit: If you want the array to have a single dimension for whatever reason, you can use [typeNum+typeNum*valueNum].
(valueNum is the position it would have in the double array, not it's actual number, ofc).

Sure.

1. int numTypes = 6;
2. //other code
3. void draw
   
4. {
   
5.       //your other code
6.       for(int h = 0; h<numTypes; h++){
   
7.             for (int i=0; i<numPoints; i++) {
   
8.                   float value = values[h][i];
9.                   float x = width - (width / numPoints) * i;
10.                   float y = height - value;
11.                   vertex(x, y);
12.       }
    
13.   }
14. }
    
15. void storeval() {
16. for(int h = numTypes; h >= 0; h--){
    
17.   for (int i = numPoints-2; i >= 0; i--) {
18.     values[h+1][i+1] = values[h][i];
19.   }
20. }

Since the data is just linked to the mouse position, all of the data will be that same mouse position, so you'll have to make it so that each type corresponds to the data you need. Also, you don't have to use "h," in the double aray, I just use h cause it spells "hi" when using a double array, lol.

You don't have the double array in the draw loop (see the code I posted for details). And that's where you declare what the value is equal to, so that's where you would input the data.
edit: Also, you have to declare it as "float[][] values;" now (on the 3rd/4th line in the code you posted). Sorry I forgot about that.

Once again, thank you for your help.