not drawing enough lines (array), why?

in Programming Questions • 1 years ago

Hi there,
I would like to draw lines, which quantity is given in an array. But processing is drawing only and always 2 lines and not more.
Here is the code:

int[][] daten = { {200,500,300,100},
                  {300, 400, 200, 350},
                  {600, 250, 300, 200},
                  {800, 300, 150, 50}
                };

int anzahlachsen = daten[0].length; // zeigt an, wieviele Punkte/Achsen es gibt // how many lines(axis)
int anzahllinie = daten.length; // zeigt an, wieviele VerbindungsLinien es gib
int x;

Achse[] achsen = new Achse[anzahlachsen];

void setup () {
size(1000,1000);
for (int i = 0; i < achsen.length; i++) {
achsen[i] = new Achse(100+x,50,100+x,500);
x = 200;
}
}
void draw() {
for (int i = 0; i < achsen.length; i++) {
    achsen[i].display();
}
}
class Achse {
color c;
int x1;
int y1;
int x2;
int y2;
int einheit;

// Konstruktor
Achse(int xpos1, int ypos1, int xpos2, int ypos2) {
c = color (0);
x1 = xpos1;
y1 = ypos1;
x2 = xpos2;
y2 = ypos2;
einheit = 20;
}

void display (){
//Achse ist nur eine Linie
stroke(c);
line (x1, y1, x2, y2);
zeigeEinheiten ();
}

void zeigeEinheiten()
{
   int y=y2;
   while (y >= y1)
   {
   line (x2, y, x2+5, y);
   y= y-einheit;
   }
}
}

Replies(2)

PhiLho

Re: not drawing enough lines (array), why?

1 years ago

You don't use the data in the array (except to get the number of objects).

for (int i = 0; i < achsen.length; i++) {
achsen[i] = new Achse(100+x,50,100+x,500);
x = 200;
}

In this loop, x is initially 0 (first line), then all the other lines use x at 200. So you have several lines, but at the same place.

l4l4l4l4

Re: not drawing enough lines (array), why?

1 years ago

thanks a lot. That's the trick. Now I put x=200+x and now it is drawing all lines. Great :-)

Top Reply

Response title

Attachments

New to this Portal?